Question

已知a-b/ab=4，则a-2ab-b/2a-2b+7ab=?, 本人数学不好，今年初一，请给出解答过程谢谢各位

Answer 1

由 (a-b)/ab=4 得a-b=4ab
代入，有 原式=(4ab-2ab)/(2*4ab+7ab)
=2ab/15ab
=2/15

Answer 2

a-b/ab=4
所以
a-b=4ab

a-2ab-b/2a-2b+7ab=[(a-b)-2ab]/[2(a-b)+7ab]=(4ab-2ab)/(2*4ab+7ab)=(2ab)/15ab=2/15

希望对您有所帮助
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谢谢您的采纳

Answer 3

因为 (a - b)/ab = 4
所以 a - b = 4ab
所以 (a - 2ab - b)/(2a - 2b + 7ab)
= [(a - b) - 2ab]/[2(a - b) + 7ab]
= (4ab - 2ab)/(8ab + 7ab)
= 2ab/15ab
= 2/15

Answer 4

(a - b)/ab = 4
a - b = 4ab
所以 (a - 2ab - b)/(2a - 2b + 7ab)
= [(a - b) - 2ab]/[2(a - b) + 7ab]
= (4ab - 2ab)/(8ab + 7ab)
= 2ab/15ab
= 2/15