Question

已知|a+b+5|+(a+2)²=0,求3a²b-[2a²b-（3ab-a²b）-4a²]-2ab的值

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Answer 1

a+2=0,a+b+5=0
a=-2,b=-3

3a²b-[2a²b-（3ab-a²b）-4a²]-2ab
=3a^2b-2a^2b+3ab-a^2b+4a^2-2ab
=4a^2+ab
=4*(-2)^2+(-2)*(-3)
=16+6
=22

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