Question

求个c++程序设计（谭浩强编的清华大学出版社）的答案

476094450@QQ.COM

Answer 1

#include<iostream>
using namespace std;
int main()
{
char a[6];
int i,k;
cin>>a;
for(i=0;i<4;i++)
{
k=a[i]-'0';
if(!(a[i]=='0'&&a[i+1]=='0'))
switch(k)
{
case 0:printf("零");break;
case 1:printf("一");break;
case 2:printf("二");break;
case 3:printf("三");break;
case 4:printf("四");break;
case 5:printf("五");break;
case 6:printf("六");break;
case 7:printf("七");break;
case 8:printf("八");break;
case 9:printf("九");break;
default:break;
}
if(k!=0)
{ switch(i)
{
case 0:printf("万");break;
case 1:printf("千");break;
case 2:printf("百");break;
case 3:printf("十");break;
default:break;
}
}
}
if(a[4]!='0')
{
k=a[4]-'0';
switch(k)
{
case 0:printf("零");break;
case 1:printf("一");break;
case 2:printf("二");break;
case 3:printf("三");break;
case 4:printf("四");break;
case 5:printf("五");break;
case 6:printf("六");break;
case 7:printf("七");break;
case 8:printf("八");break;
case 9:printf("九");break;
default:break;
}

}

return 0;

}

Answer 2

恩，我发你你邮箱里

Answer 3

自己做！

Answer 4

#include <iostream>
using namespace std;
class aa
{public:
aa(int a);
aa();
aa operator +(aa b);
void display();
private:
int m; };
int main()
{
aa c1(4),c2(5),c3;
c3=c1+c2;
c3.display();
return 0;
}
aa::aa(int a)
{m=a;}
aa::aa()
{m=0;}
void aa::display()
{cout<<m<<endl;}
aa aa::operator +(aa b)
{aa b1;
b1.m =m+b.m;
return b1;}