Question

C语言问题，编写一个程序计算矩形的面积和周长

我是新手，很多不懂，初学。

Answer 1

楼上的写的太高端,我来的简单直接的.

#include <stdio.h>
main()
{
int s,c,x,y;
scanf("%d,%d",x,y);
s=x*y;
c=(x+y)*2;
printf("面积为%d\n",s);
printf("周长为%d\n",c);
}

Answer 2

#include <iostream>
using namespace std;

class Rect
{
private:
int l, w;
public:
Rect(int len = 0, int wid = 0) : l(len), w(wid)
{
}

Rect(const Rect& rect)
{
l = rect.l;
w = rect.w;
}

int getArea() const//定义面积
{
return l * w;
}

int getPerimeter() const//定义周长
{
return (l + w) * 2;
}

};

int main()
{
Rect r1;
Rect r2(3, 5);
cout << "len "<<r1.getArea() << "\t" << "wid "<<r1.getPerimeter() << endl;
cout << "Area "<<r2.getArea() << "\t" << "Perimeter "<<r2.getPerimeter() << endl;
return 0;
}

Answer 3

我认为这样写更好
#include <stdio.h>
main()
{
int x,y;
scanf("%d,%d",x,y);
printf("面积为%d\n",x*y);
printf("周长为%d\n",(x+y)*2);
}

Answer 4

#include <stdio.h>
void main()
{
int x,y;
printf("enter the data\n");
scanf("%d,%d",&x,&y);
printf("面积为%d\n",x*y);
printf("周长为%d\n",(x+y)*2);
}

Answer 5

#include<stdio.h>
int main()
{
float a,b;
float area,circuit;
scanf("%d%d",a,b);
printf("area=%d\n circuit=%d\n");
getchar();
getchar();
}