若m-n=4,mn=-1,求代数式（9-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值
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（9-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)
=9-2mn+2m+3n-3mn-2n+2m-m-4n-mn
=9-6mn+3m-3n
=9-6mn+3(m-n)
=9-6×(-1)+3×4
=9+6+12
=27
=9-2mn+2m+3n-3mn-2n+2m-m-4n-mn
=9-6mn+3m-3n
=9-6mn+3(m-n)
=9-6×(-1)+3×4
=9+6+12
=27
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（9-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)
=9-2mn+2m+3n-3mn-2n+2m-m-4n-mn
=9-2mn-mn-3mn+2m+2m-m+3n-2n-4n
=9-6mn+3m-3n
=9-6mn+3(m-n)
=9-6*(-1)+3*4
=9+6+12
=27
=9-2mn+2m+3n-3mn-2n+2m-m-4n-mn
=9-2mn-mn-3mn+2m+2m-m+3n-2n-4n
=9-6mn+3m-3n
=9-6mn+3(m-n)
=9-6*(-1)+3*4
=9+6+12
=27
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27
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