分解因式:(2x+y)^2-(x+2y)^2
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(2x+y)^2-(x+2y)^2
=(2x+y+x+2y)(2x+y-x-2y)
=(3x+3y)(x-y)
=3(x+y)(x-y)
=(2x+y+x+2y)(2x+y-x-2y)
=(3x+3y)(x-y)
=3(x+y)(x-y)
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展开全部
(2x+y)^2-(x+2y)^2
=(2x+y+x+2y)(2x+y-x-2y)
=(3x+3y)(x-y)
=3(x+y)(x-y)
=(2x+y+x+2y)(2x+y-x-2y)
=(3x+3y)(x-y)
=3(x+y)(x-y)
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:(2x+y)^2-(x+2y)^2
=[﹙2x+y﹚+﹙x+2y﹚][﹙2x+y﹚-﹙x+2y﹚]
=﹙3x+3y﹚﹙x-y﹚
=3﹙x+y﹚﹙x-y﹚
=[﹙2x+y﹚+﹙x+2y﹚][﹙2x+y﹚-﹙x+2y﹚]
=﹙3x+3y﹚﹙x-y﹚
=3﹙x+y﹚﹙x-y﹚
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(2x+y)^2-(x+2y)^2
=[(2x+y)-(x+2y)][(2x+y)+(x+2y)]
=(2x+y-x-2y)(2x+y+x+2y)
=(x-y)(3x+3y)
=3(x-y)(x+y)
=[(2x+y)-(x+2y)][(2x+y)+(x+2y)]
=(2x+y-x-2y)(2x+y+x+2y)
=(x-y)(3x+3y)
=3(x-y)(x+y)
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