Question

一道简单的高数极限题

Lim (cotx)^(1/lnx) X趋向于正无穷

Answer 1

e^(limlncotx/lnx)
=e^lim(-csc^2x/cotx)/(1/x)
=e^lim(-x/sinxcosx)
=e^(-1) (x应该趋向于+0)

Answer 2

=lime^(lncotx/lnx)
=e^lim(lncotx/lnx)
=e^lim(-tan*cscx^2)/(1/x)
=e^lim[-1/cosx*(x/sinx)]
=e^-1
书上例题= =