Question

[log(4)3+log(8)3][log(3)2+log(9)8]

咋解，要过程，帮个忙吧

Answer 1

log(4)3=lg3/2lg2
log(8)3=lg3/3lg2
log(3)2=lg2/lg3
log(9)8=3lg2/2lg3
原式=(lg3/2lg2+lg3/3lg2)(lg2/lg3+3lg2/2lg3)
=5lg3/6lg2×5lg2/2lg3
=25/12
谢谢~_~