Question

contextmenustrip 控件,我只想让它在有内容的情况下,右键菜单才会显示,否则不显示

if (listView1.SelectedItems.Count == 0)
{

}
else
{
DialogResult dresult = MessageBox.Show("是否删除","提示",MessageBoxButtons.YesNo,MessageBoxIcon.Question);
if (dresult == DialogResult.Yes)
{
int num = 0;
try
{
DBHelper.con.Open();
string sql = string.Format("delete from stuinfo where stuid = {0}",listView1.SelectedItems[0].Tag);
SqlCommand cmd = new SqlCommand(sql,DBHelper.con);
num = cmd.ExecuteNonQuery();
}
catch (Exception ex)
{
MessageBox.Show(ex.Message);
}
finally
{
DBHelper.con.Close();
}
if (num > 0)
{
MessageBox.Show("删除成功");
listView1.Items.Clear();
xianshi();
}
else
{
MessageBox.Show("删除失败");
}

}
else
{

}
}
这是我的代码，，效果是不论是否有值，都会显示右键菜单，，
我想要的是只有右键有值的情况下，才显示右键菜单属性，右键单机没值时，就不显示值

Answer 1

写右键菜单contextMenuStrip1的Opening事件

private void contextMenuStrip1_Opening(object sender, CancelEventArgs e)
{
if (listView1.SelectedItems.Count == 0)
{
e.Cancel = true;
}
}