Question

16x的五次方-8x的三次方y的平方+xy的四次方

Answer 1

=x(16x^4-8x²y²+y^4)
=x(4x²-y²)²
=x(2x+y)²(2x-y)²

Answer 2

16x的五次方-8x的三次方y的平方+xy的四次方
=x(16x^4-8x^2y^2+y^4)
=x(4x^2-y^2)^2
=x[(2x+y)(2x-y)]^2
=x(2x+y)^2(2x-y)^2