Question

如何让循环输出的字符串每次叠加在一起连接起来？

int a =Integer.parseInt(request.getParameter(dFlower.get(i).getSelFlowerName()));
if(a==0)
{

}else
{
System.out.println(dFlower.get(i).getSelFlowerName()+a+"只");;
//上边是每次输出的caiLiao
count+=dFlower.get(i).getPrice()*a;
}
}
hua.setCaiLiao(caiLiao);
如 火百合(支)10只
黄康乃馨(支)11只

Answer 1

假设i为连续输出的字符串
public static void main(String[] args) {
StringBuilder sb = new StringBuilder();
for(int i=0;i<10;i++){
sb.append(i);
}
System.out.println("结果为："+sb);
}
结果为：0123456789