Question

error C2664: 'strcpy' : cannot convert parameter 1 from 'int' to 'char *'

#include<stdio.h>
#include<string.h>
#include<iostream>
#define N 3
void main()
{
void input(int num[],char name[][8]);
void sort(int num[],char name[N][8]);
void search(int n,int num[],char name[N][8]);
int num[N];
char name[N][8],c;
int n,flag=1;
input(num,name);
sort(num,name);
while(flag=1)
{
scanf("%d",&n);
search(n,num,name);
if((c=getchar())=='n')
flag=0;
}
}
void input(int num[],char name[N][8])
{
int i;
for(i=0;i<N;i++)
{
printf("please inpput number:");
scanf("%d",&num[i]);
gets(name[i]);
}
}
void sort(int num[],char name[N][8])
{
int i,j,temp;
char temp1[8];
for(i=0;i<N-1;i++)
{
for(j=i;j<N;j++)
{if(num[i]>num[j])
{
temp=num[i];num[i]=num[j];num[j]=temp;
strcpy(temp1,name[i]);
strcpy(name[i],name[j]);
strcpy(num[j],temp1);
}
}
}
}
void search(int n,int num[],char name[N][8])
{

int i;
int top=0,bot=N-1,mid;
while(top<=bot)
{
mid=(top+bot)/2;
if(n>num[mid])
top=mid+1;
else if(n<num[mid])
bot=mid-1;
else{ printf("the time%d is:",num[mid]);
puts(name[mid]);
}
}
}

Answer 1

strcpy不能把char复制到int型
strcpy(num[j],temp1);

Answer 2

保护环境作文