Question

JSP mysql 求助：打开http://localhost:8080/myapp/first.jsp出现以下错误代码是什么意思？

HTTP Status 500 -

--------------------------------------------------------------------------------

type Exception report

message

description The server encountered an internal error () that prevented it from fulfilling this request.

exception

org.apache.jasper.JasperException: Unable to compile class for JSP

An error occurred at line: 5 in the jsp file: /myapp/first.jsp
Generated servlet error:
D:\Tomcat5.0\work\Catalina\localhost\_\org\apache\jsp\myapp\first_jsp.java:48: unclosed string literal

An error occurred at line: 5 in the jsp file: /myapp/first.jsp
Generated servlet error:
String url ="jdbc:mysql:
^

An error occurred at line: 5 in the jsp file: /myapp/first.jsp
Generated servlet error:
D:\Tomcat5.0\work\Catalina\localhost\_\org\apache\jsp\myapp\first_jsp.java:51: unclosed string literal
true&characterEncoding=8859_1"
^
2 errors

org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:84)
org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:332)
org.apache.jasper.compiler.Compiler.generateClass(Compiler.java:412)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:472)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:451)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:439)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:511)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:295)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:292)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:236)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

note The full stack trace of the root cause is available in the Apache Tomcat/5.0.28 logs.
。。

Answer 1

Unable to compile class for JSP
不能把jsp编译成servlet
估计是.jsp文件写的有问题

Answer 2

服务器内部错误
看你的 文件first_jsp.java
的48和51行有什么错误？