Question

求shell脚本，删除一个txt文档中包含另外一个txt文档的行。

Answer 1

#!/usr/bin/ksh
###[局部方法]########################
SedFileCont()
{
_fileName=$1
_fromContent=$2
_toContent=$3

vi $_fileName <<! >/dev/null
:1,%s/$_fromContent/$_toContent/g
:x
!

}
###[局部方法]########################

#需要删除行的txt:src.txt
#执行匹配行的txt:std.txt
###[执行修改]########################

cat std.txt|while read strLine
do
cnt=0
cat src.txt|grep ${strLine}|wc -l|read cnt
[ $cnt -eq 0 ] && continue
[ $cnt -gt 0 ] && SedFileCont src.txt ${strLine} "\c"
done

###[执行修改]########################

Answer 2

#!/bin/bash
#
# assume /tmp/a.txt is the file for keywords
# /tmp/b.txt is the file to be operated

awk '
BEGIN{
i=0

while(getline < "/tmp/a.txt" > 0) {
keyword[i++] = $0
}

keysize=i
}

{
flag=0
for(i=0;i<keysize;i++)
if($0 ~ keyword[i])
flag=1

if(flag==0)
print
}' /tmp/b.txt > /tmp/b.txt.tmp

# replace /tmp/b.txt with modified /tmp/b.txt.tmp
mv /tmp/b.txt.tmp /tmp/b.txt

把上述代码保存为脚本。调试：
debian:~/prog/shell# cat /tmp/a.txt
abc def
def
kllmn
delete
debian:~/prog/shell# cat /tmp/b.txt
#!/bin/bash

delete
kllmn

执行脚本后：
debian:~/prog/shell# cat /tmp/b.txt
#!/bin/bash