Question

已知x²-5x+1=0求x³-4x²-4x-1的值

Answer 1

x3-4x2-4x-1=x3-5x2+x+x2-5x+1-2=x(x2-5x+1)+x2-5x+1-2=-2
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Answer 2

已知x²-5x+1=0
x³-4x²-4x-1=x(x²-5x)+x²-4x-1
=x·（-1）+x²-4x-1
=x²-5x-1
=-1-1
=-2

Answer 3

x^3-4x^2-4x-1
=(x^2-5x+1)x+x^2-5x-1
=0x+0-2
=-2
对吗