Question

分解因式：ax³-ax²+ax-a

运用平方差、和提公因式法分解因式

Answer 1

ax³-ax²+ax-a=ax²(x-1)+a(x-1)=a(x²+1)(x-1)

Answer 2

ax³-ax²+ax-a=a(x³-x²+x-1)=a[x²(x-1)+(x-1)]=a(x-1)(x²+1)

Answer 3

ax³-ax²+ax-a
=a[﹙x³－x²﹚＋﹙x－1﹚]
=a﹙x－1﹚﹙x²＋1﹚