Question

C#怎么计算给定时间与当前时间的差

在WINFORM中用datetimepicker给定时间，精确到秒
以秒为单位，得到一个int型的数据

Answer 1

TimeSpan t1 ;

DateTime d1 = DateTime.Now;

DateTime d2 = DateTime.Now.AddMinutes(1);

t1 = d2 - d1;

double m = t1.TotalSeconds;//时间差为秒。

追问

怎么调用dateTimePicker的值，我的控件名字是dateTimePicker1

追答

DateTime dt = dateTimePicker1.Value;

Answer 2

dateTimePicker1.Value = new DateTime(2000, 12, 31, 12, 59, 1);
var dt = new DateTime(2000, 12, 31, 12, 59, 59);
var diff = dt - dateTimePicker1.Value;
MessageBox.Show(diff.ToString() +", "+ diff.TotalSeconds.ToString());

Answer 3

C#里使用Timespan ，

DateTime start = DateTime.Now;
Thread.Sleep(2000);
TimeSpan sp = DateTime.Now - start;
MessageBox.Show(sp.TotalSeconds.ToString());

Answer 4

两个时间对象做减法会得到个时间片对象，这个时间片就是是时间差。

Answer 5

datetimepicker的Format属性 设置你需要的格式
int str =int.parse( (dateTimePicker1.Value - dateTimePicker2.Value).ToString());