Question

请教C语言高手,这个continue究竟错在哪里?dev c++老是显示continue statement not within a loop

#include<stdio.h>
#include<stdlib.h>
int main(void)
{
const float MIN = 0.0f;
const float MAX = 100.0f;

float score;
float total = 0.0f;
int n = 0;
float min = MAX;
float max = MIN;

printf("Enter the first score (q to quit):");
while(scanf("%f", &score) == 1);
{
if(score < MIN || score > MAX)
{
printf("%0.1f is an invalid value.Try again: ",
score);
continue;
}
printf("Accpting %0.1f: \n", score);
min = (score < min)? score: min;
max = (score > max)? score: max;
total += score;
n++;
printf("Enter next score (q to quit):");
}
if(n > 0)
{
printf("Average of %d scores is %0.1f.\n", n, total / n);
printf("Low = %0.1f, higt = %0.1f\n", min, max);
}
else
printf("No valid scores were entered.\n");
system("pause");
return 0;
}

Answer 1

while循环语句后面多了个分号
导致 编译器认为continue不在循环的内部
把分号删掉即可

Answer 2

while(scanf("%f", &score) == 1) 后面多了个分号，导致后面的continue没有在循环语句之中使用。

Answer 3

continue语句不能方在if语句中，只能放到循环语句中

Answer 4

while(scanf("%f", &score) == 1) 后面多了个分号！！！