Question

c语言 请问char数组该如何声明？

#include <string.h>
#include <stdio.h>
void main()
{
char a[]={"abc","defdsf","dsaf"};
// char *a;
// a=(char *)malloc(100*sizeof(char));
//a[]={"SDF","Hds","sadf"};
char *e[5];
strcpy(e[1],a[1]);
printf("%s",e[1]);
}

Answer 1

char数组的声明就是直接定义一个char类型的数组。

声明一个char型数组：
char a[N] // a为char型数组名，N为数组大小
值得注意的是：声明必须要在调用之前，对于C语言，必须将定义的语句放在执行功能语句之前。

Answer 2

char a[3][7]={"abc","defdsf","dsaf"};
中括号里的每个字符串，都应该用一个数组来保存了，所以这是一个二维数组。

Answer 3

#include <stdio.h>

int main()
{
int i;
char ch[5] = {'a','b','c','d','\0'};//方式1
char ch2[]="hello";//方式2
char *ch3 = "world";//方式3
char *ch4[3] = {"welcome", "," ,"doudou745"};//字符指针数组
printf("%s\n", ch);
printf("%s\n", ch2);
printf("%s\n", ch3);
for (i = 0; i < 3; i++)
{
printf("ch4[%d] = %s\n", i+1, ch4[i]);
}

return 0;
}

追问

假如我想將ch4[2]的值strcpy給ch2呢，要怎麼寫呢？

追答

#include
#include

int main()
{
int i;
char ch[5] = {'a','b','c','d','\0'};//方式1
char ch2[]="hello";//方式2
char *ch3 = "world";//方式3
char *ch4[3] = {"welcome", "," ,"doudou745"};//字符指针数组
printf("%s\n", ch);
printf("%s\n", ch2);
printf("%s\n", ch3);
for (i = 0; i < 3; i++)
{
printf("ch4[%d] = %s\n", i+1, ch4[i]);
}
strcpy(ch2,ch4[2]);
printf("%s\n", ch2);
return 0;
}