Question

(x-3)分之x-(x^2-3x)分之(x+6)+x分之1等于几？

[x+1-(1-x)分之1]除以[x-(x-1)分之x^2]等于几？
两道题目，希望哥哥姐姐们看看啊~~【做了好几次都米有做出来。。。

Answer 1

(x-3)分之x-(x^2-3x)分之(x+6)+x分之1等于几？
=x²/x(x-3)-(x+6)/x(x-3)+(x-3)/x(x-3)
=(x²-x-6+x-3)/x(x-3)
=(x²-9)/x(x-3)
=(x+3)/x

[x+1-(1-x)分之1]除以[x-(x-1)分之x^2]等于几？
=[(x+1)+1/(x-1)] ×(x-1)/(-x)
=x²/(x-1) ×(x-1)/(-x)
=-x

Answer 2

(x-3)分之x-(x^2-3x)分之(x+6)+x分之1等于几？
=x²/x(x-3)-(x+6)/x(x-3)+(x-3)/x(x-3)
=(x²-x-6+x-3)/x(x-3)
=(x²-9)/x(x-3)
=(x+3)/x

[x+1-(1-x)分之1]除以[x-(x-1)分之x^2]等于几？
=[(x+1)+1/(x-1)] ×(x-1)/(-x)
=x²/(x-1) ×(x-1)/(-x)
=-x

Answer 3

通分吧，慢慢算

Answer 4

道篇