Question

C语言中出现cannot convert parameter 1 from 'char [9][3]' to 'char []'

源代码为#include <stdio.h>
#include <string.h>
void changeinto(char a[],char b[]);
char money[][4]={"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};
char a[][3]={"元","拾","佰","仟","万","拾","佰","仟","亿"};
void main()
{

char b[10];
printf("please input money\n");
gets(b);
changeinto(a,b);

}
void changeinto(char a[],char b[])
{
int i,j=0,n=strlen(b);
for(i=0;i<n;i++)
j=a[i]-'0';
printf("%s",a[j]);
}

Answer 1

编译问题是改好了，但是你的程序逻辑有问题，自己找一找吧，
#include <stdio.h>
#include <string.h>
void changeinto(char b[]);
char money[][4]={"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};
char a[][3]={"元","拾","佰","仟","万","拾","佰","仟","亿"};
void main()
{

char b[10];
printf("please input money\n");
gets(b);
changeinto(b);

}
void changeinto(char b[])
{
int i,j=0,n=strlen(b);
for(i=0;i<n;i++)
j=a[i][0]-'0';
printf("%s",a[j]);
}
提示一下：
钱数依次取最高位，将最高位值和money匹配，将最高位的位数和a匹配

Answer 2

有几个错误，注意注释处：
#include <stdio.h>
#include <string.h>
void changeinto(char (*a)[3],char b[]); /* a[] */
char money[][4]={"零","壹","贰","叁","肆","伍","陆","柒","捌","玖"};
char a[][3]={"元","拾","佰","仟","万","拾","佰","仟","亿"};
void main()
{

char b[10];
printf("please input money\n");
gets(b);
changeinto(a,b);
}
void changeinto(char (*a)[3],char b[]) /* a[] */
{
int i,j=0,n=strlen(b);
for(i=0;i<n;i++){
j=b[i]-'0'; /* a[i] */
printf("%s",a[j]);}
}

Answer 3

参数传递要匹配，二维不能传给一维