Question

一元一次方程啊、、求帮助、、数学高手请进。。。。。。。

x(1+153.94％）=3611

2[x+(x+25)]=310

一元一次方程求过程

要过程啊啊啊啊啊啊。。。

Answer 1

1、 原始可得
2.5394x=3611
x=3611/2.5394
x=1421.9894
2、原始可得
2*（x+x+25）=310
2x+2x+50=310
4x=310-50
4x=260
x=65

Answer 2

x(1+153.94％）=3611
2.5394x=3611
x=1 421.9894463259

2[x+(x+25)]=310
2(2x+25)=310
4x+50=310
4x=260
x=65

Answer 3

x(1+153.94％）=3611
x=3611÷(1+153.94%)
=3611÷2.5394
≈1421.99
2[x+(x+25)]=310
x+x+25=310÷2
2x=155-25
x=130÷2
x=65

Answer 4

1、x(1+1.5394)=3611
2.5394x=3611
x=3611/2.5394
x=1421.989446325903756792943214932
题目是不是有问题啊？除不尽的啦
2、2(x+x+25)=310
2(2x+25)=310
4x+50=310
4x=310-50
4x=260
x=260/4
x=65

Answer 5

1.x+1.5394x=3611
2.5394x=3611
x=3611/2.5394
2.2(2x+25)=310
4x+50=310
4x=260
x=65