Question

幂级数展开求助！！

sin(z/(1-z))=sigema 0-->无穷 (Cn(z-1)^n)
求Cn

Answer 1

sin(z/(1-z))=-Σ(0++)(z/(z-1))＾(2n+1)/(2n+1)!*(-1)＾n
又等于Σ(0++)Cn(z-1)＾n
则Cn＝-(-1)＾n*z＾(2n+1)*(z-1)＾(-3n-1)/(2n+1)!