Question

仓库里有一批面粉，运走总数的八分之五后，又运进270袋，这时仓库里的面粉恰好是原来的七分之六，仓库里原

用方程解

Answer 1

=270÷（6/7-3/8）+560袋

Answer 2

设原来有x袋
x(1-5/8)+270=6/7x
3/8x+270=6/7x
6/7x-3/8x=270
27/56x=270
x=560
答：原来有560袋

Answer 3

设原来有X袋
由题列方程
X-（5/8)X+270=(6/7)X
X=560

Answer 4

解：设原有X袋
X-5/8X+270=6/7x
X=560

Answer 5

设原来创库有X袋
则有
6/7X-5/8X=270

Answer 6

x-5x/8+270=6x/7 x=560