
2个回答
展开全部
(x+2)/(x+1)-(x+3)/(x+2)=(x+4)/(x+3)-(x+5)(x+4)
左边=1+1/(x+1)-1-1/(x+2)=1/(x+1)-1/(x+2)=1/(x+1)(x+2)
右边=1+1/(x+3)-1-1/(x+4)=1/(x+3)-1/(x+4)=1/(x+3)(x+4)
1/(x+1)(x+2)=1/(x+3)(x+4)
即(x+1)(x+2)=(x+3)(x+4)
x^2+3x+2=x^2+7x+12
-10=4x
x=-5/2
左边=1+1/(x+1)-1-1/(x+2)=1/(x+1)-1/(x+2)=1/(x+1)(x+2)
右边=1+1/(x+3)-1-1/(x+4)=1/(x+3)-1/(x+4)=1/(x+3)(x+4)
1/(x+1)(x+2)=1/(x+3)(x+4)
即(x+1)(x+2)=(x+3)(x+4)
x^2+3x+2=x^2+7x+12
-10=4x
x=-5/2
展开全部
对 就是这样 (x+2)/(x+1)-(x+3)/(x+2)=(x+4)/(x+3)-(x+5)(x+4)
左边=1+1/(x+1)-1-1/(x+2)=1/(x+1)-1/(x+2)=1/(x+1)(x+2)
右边=1+1/(x+3)-1-1/(x+4)=1/(x+3)-1/(x+4)=1/(x+3)(x+4)
1/(x+1)(x+2)=1/(x+3)(x+4)
即(x+1)(x+2)=(x+3)(x+4)
x^2+3x+2=x^2+7x+12
-10=4x
x=-5/2
左边=1+1/(x+1)-1-1/(x+2)=1/(x+1)-1/(x+2)=1/(x+1)(x+2)
右边=1+1/(x+3)-1-1/(x+4)=1/(x+3)-1/(x+4)=1/(x+3)(x+4)
1/(x+1)(x+2)=1/(x+3)(x+4)
即(x+1)(x+2)=(x+3)(x+4)
x^2+3x+2=x^2+7x+12
-10=4x
x=-5/2
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