Question

用c++编写一个程序,用指向函数的指针实现求两个实数中的较大値和较小值

Answer 1

#include <iostream>
using namespace std;

int max(int num1, int num2)
{
return (num1>=num2 ? num1 : num2);
}

int min(int num1, int num2)
{
return (num1<=num2 ? num1 : num2);
}

main()
{
int *fun(int, int);
int a = 10, b = 20;
fun = max;
count<<"the larger integer is: "<<fun(a, b)<<endl;
fun = min;
count<<"the smaller integer is: "<<fun(a, b)<<endl;
}

Answer 2

#include<iostream>
using namespace std;

float max(float x,float y)
{
return(x>y?x:y);
}

void main()
{
float (*ptr)(float, float);
float a,b,c;

ptr=max;

cin>>a>>b;

c=(*ptr)(a,b);

cout<<"a="<<a<<",b="<<b<<",max="<<c;
}

Answer 3

#include "stdio.h"

float max(float a,float b)
{
return a>b?a:b;
}
float min(float a,float b)
{
return a<b?a:b;
}
void main()
{
float (*fun)(float,float);
float a = 1,b = 2;
fun = max;
printf("Max=%f\n",(*fun)(a,b));
fun = min;
printf("Min=%f\n",(*fun)(a,b));
}