Question

已知线段AB,延长到AB到点C ,使BC=二分之一AB,反延长AB到点D,使AD=二分之三AB,CD=26，求AB长

Answer 1

设AB长为a，则26=a+2a/3+a/2,得到a=12,即AB长为12.

Answer 2

解
AD＝3AB/2
BC＝AB/2
DC＝AD+AB+BC＝3AB/2+AB+AB/2＝3AB＝26
AB＝26/3