Question

用matlab实现x(n)=0.8^n 和x(n)=e^[(0.2+3j)n] (0<=n<=15)

Answer 1

x = @(n) 0.8.^n
n = 0:15;
x(n)
x(n)'

x1 = @(n) exp((0.2+3j).*n)
n = 0:15;
x1(n)
x1(n)'

Answer 2

n=0:15;
x_1=0.8.^n;
x_2=exp((0.2+3*i).*n);