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解
2x+y=6
x-3y=1
-y(x-3y)^2+2x(3y-x)^3
=-Y(X-3Y)^2-2X(X-3Y)^3
=-(X-3Y)^2×[Y+2X(X-3Y)]
=-1×(Y+2X)
=-1×6
=-6
2x+y=6
x-3y=1
-y(x-3y)^2+2x(3y-x)^3
=-Y(X-3Y)^2-2X(X-3Y)^3
=-(X-3Y)^2×[Y+2X(X-3Y)]
=-1×(Y+2X)
=-1×6
=-6
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