Question

请编写关于数组的C语言程序

任意输入10个学生的成绩存放在数组中，
然后输出最高分、最低分，以及不及格的人数，以其在成绩中人数的比例。

Answer 1

#include <stdio.h>
#include <stdlib.h>
#define STU 10 //宏定义学生人数，改起来方便
#define SCORE 60 //学生及格分数线

int main()
{
int score[STU];
int i;
int j;
int t;
int num = 0;
printf("please input ten number:");
for(i = 0; i < STU; i++)
{
scanf("%d",&score[i]);
}

for(i = 0; i < STU; i++)
{
for(j = 0; j < STU-1; j++)
{
if(score[j]>score[j+1])
{
t = score[j];
score[j] =score[j+1];
score[j+1] = t;
}
}
}
printf("The high score is :%d\n",score[STU-1]);
printf("The low score is :%d\n",score[0]);
for(i = 0; i < STU; i++)
{
if(score[i] < SCORE)
{
num++;
}
else
break;
}
printf("The count of students to fail is :%0.2f %%\n",100*(float)num/STU);
return 0;
}
用冒泡写感觉简单点。

追问

加上输出不及格的人数

追答

#include
#include
#define STU 10 //宏定义学生人数，改起来方便
#define SCORE 60 //学生及格分数线

int main()
{
int score[STU];
int i;
int j;
int t;
int num = 0;
printf("please input ten number:");
for(i = 0; i score[j+1])
{
t = score[j];
score[j] =score[j+1];
score[j+1] = t;
}
}
}
printf("The high score is :%d\n",score[STU-1]);
printf("The low score is :%d\n",score[0]);
for(i = 0; i < STU; i++)
{
if(score[i] < SCORE)
{
num++;
}
else
break;
}
printf("The count of students to fail is:%d\n",num);
printf("The rate of students to fail is :%0.2f %%\n",100*(float)num/STU);
return 0;
}

Answer 2

#include <stdio.h>
#define N 10
void main()
{
float s[N],max,min;
int i,j;
printf("输入学生成绩：\n");
for(i=0;i<N;i++)
scanf("%f",&s[i]);
min=max=s[0];
for(i=0,j=0;i<N;i++)
{
if(min>s[i])
min=s[i];
if(max<s[i])
max=s[i];
if(s[i]<60)
j++;
}
printf("最高分是：%f,最低分是：%f,不及格的学生有%f人占：%f",max,min,j,100*(float)j/N);
printf("%%\n");
}