Question

求十个一元一次方程（去括号、分母、一项）详细过程加答案

Answer 1

2x-1/2+3(3x+2)/3=27

追问

.....我要10个..

追答

x-2/21-7-x/3=1
120x/80(42-x)=2/1
2x-12/3=27-x/2
4x/2-3=3/4
5x-3/2=6/1+3/4
42y+1=33-2y/2
5y+11=11/3-3
45-1/3+x/4=5/6+2/3
x-2/2006+x/2008+x+2/4010=6

Answer 2

2x+3=5
2x+3-3=5-3
2x=2
x=1

Answer 3

x-2/21-7-x/3=1