Question

编写servlet后为什么老是提醒404错误，改了很多路径仍然不行，求高手赐教

<form name="form1" method="post"action="/AreaServlet">
<p>边A:<input name=sideA type="text" /></p>
<p>边B:<input name=sideB type="text" /></p>
<p>边C:<input name=sideC type="text" /></p>
<P><input name="submit" type="submit" value="提交"/></P>

</form>

web.xml

<servlet>
<servlet-name>Area</servlet-name>
<servlet-class>/sourcech10.AreaServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Area</servlet-name>
<url-pattern>/AreaServlet</url-pattern>
</servlet-mapping>

Answer 1

form表单的action中的"/"去掉.
配置servlet时class中"/sourcech10.AreaServlet"的"/"去掉.还有该类是否继承了HttpServlet类.改写dopost方法.

Answer 2

<servlet-mapping>
<servlet-name>Area</servlet-name>
<url-pattern>/AreaServlet</url-pattern>
</servlet-mapping>
把这个<url-pattern>/AreaServlet</url-pattern>里的/去了

<form name="form1" method="post"action="/AreaServlet">
应该写成
<form name="form1" method="post"action="AreaServlet">

Answer 3

<servlet>
<servlet-name>Area</servlet-name>
<servlet-class>sourcech10.AreaServlet</servlet-class>
</servlet>
还有表单中的 action的/也去掉

Answer 4

<servlet>
<servlet-name>Area</servlet-name>
<servlet-class>sourcech10.AreaServlet</servlet-class> 这里改改，
</servlet>

Answer 5

/sourcech10.A.....前面的/去掉，
action="<%=request.getContextPath() %>/AreaServlet"
或者action="AreaServlet"二者皆可