Question

跪求简单的java程序啊!!用java编写一个项目，要有界面GUI的，不要那么复杂，但是要能运行的!!

程序代码要有注释的，本人代码方面很弱。。现在是完全没有思路要做什么啊，我只想做出简单一点的项目，适合初学者的)大家有什么提议都可以提出来，拜托了!!!!感激不尽!!

Answer 1

验证登陆的，用户名admin, 密码abc123的时候通过，如果超过3次程序退出

import java.awt.BorderLayout;
import java.awt.GridLayout;
import java.awt.event.MouseEvent;
import java.awt.event.MouseListener;

import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JLabel;
import javax.swing.JOptionPane;
import javax.swing.JPanel;
import javax.swing.JPasswordField;
import javax.swing.JTextField;

public class Logon {

private JFrame f = new JFrame("Logon");
private JTextField username = new JTextField(10);
private JPasswordField password = new JPasswordField(10);
private JLabel user = new JLabel("User");
private JLabel pwd = new JLabel("Password");
private JButton logon = new JButton("Logon on");
private int count = 0;

public Logon(){
JPanel p = new JPanel();
p.setLayout(new GridLayout(2, 2));

p.add(user);
p.add(username);
p.add(pwd);
p.add(password);

f.add(p, BorderLayout.NORTH);
f.add(logon, BorderLayout.SOUTH);

logon.addMouseListener(new MouseListener(){

public void mouseClicked(MouseEvent e) {
if(count < 3){
if(username.getText().trim().equals("") || password.getText().trim().equals("")){
JOptionPane.showMessageDialog(null, "Password/Username is blank. Please input!");
return;
}

if(username.getText().equals("admin") && password.getText().equals("abc123")){
JOptionPane.showMessageDialog(null, "Logon on success");
}else{
username.setText("");
password.setText("");
JOptionPane.showMessageDialog(null, "Username/password incorrect. Please try again");
count++;
}

}else{
JOptionPane.showMessageDialog(null, "You have tried 3 times. Program exit!");
System.exit(0);
}

}

public void mouseEntered(MouseEvent e) {}
public void mouseExited(MouseEvent e) {}
public void mousePressed(MouseEvent e) {}
public void mouseReleased(MouseEvent e) {}
});

f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
f.setVisible(true);
f.setBounds(200, 200, 400, 400);
f.pack();

}

public static void main(String[] args) {
new Logon();
}

}

Answer 2

我认为你从最基础的书看起 ，不要一味追求最新，只要了解最基础的 你才能更好的利用它

Answer 3

System.out.println("你好！");