sin(-26/6π)sin(-46/3π)-cos(-37/6π)tan(-55/6π)求值,急急急!!!
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sin(-26/6π)sin(-46/3π)-cos(-37/6π)tan(-55/6π)
=sin(4π-26/6π)sin(16π-46/3π)-cos(6π-37/6π)tan(10π-55/6π)
=sin(-1/3π)sin(2/3π)-cos(-1/6π)tan(5/6π)
=-sin(1/3π)sin(π-1/3π)-cos(1/6π)tan(π-1/6π)
=-sin(1/3π)sin(1/3π)+cos(1/6π)tan(1/6π)
=-√3/2*√3/2+√3/2*√3/3
=-3/4+1/2
=-1/4
=sin(4π-26/6π)sin(16π-46/3π)-cos(6π-37/6π)tan(10π-55/6π)
=sin(-1/3π)sin(2/3π)-cos(-1/6π)tan(5/6π)
=-sin(1/3π)sin(π-1/3π)-cos(1/6π)tan(π-1/6π)
=-sin(1/3π)sin(1/3π)+cos(1/6π)tan(1/6π)
=-√3/2*√3/2+√3/2*√3/3
=-3/4+1/2
=-1/4
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