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y=arcsin[(1-x)/(1+x)] [(1-x)/(1+x)]'=[2/(1+x)-1]'=-2/(1+x)^2
y'= [-2/(1+x)^2] *[1/√[1-(1-x)^2/(1+x)^2]]
= -2/[(1+x)√(4x)
= -1/[(1+x)√x]
y=[(1-x)/(1+x)]^(1/3)
y'=[-2/(1+x^2)]*(1/3)*[(1-x)/(1+x)]^(-2/3)
y=x+lny
y'=1+y'/y
y'(1-1/y)=1
y'=1/(1-1/y)=y/(y-1)=(x+lny)/(x+lny-1)
y'= [-2/(1+x)^2] *[1/√[1-(1-x)^2/(1+x)^2]]
= -2/[(1+x)√(4x)
= -1/[(1+x)√x]
y=[(1-x)/(1+x)]^(1/3)
y'=[-2/(1+x^2)]*(1/3)*[(1-x)/(1+x)]^(-2/3)
y=x+lny
y'=1+y'/y
y'(1-1/y)=1
y'=1/(1-1/y)=y/(y-1)=(x+lny)/(x+lny-1)
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