Question

lazarus程序题：

有一个分段函数f(x)={x-2 -10<=x<-8
x+3 -8<=x<-6
x平方 -6<=x<=-2
x绝对值 -2<x<2
x三次方 2<=x<=4
3x-4 4<x<=6
4x+1 6<x<=8

帮个忙！！！谢谢你

Answer 1

function pp(i:integer):integer;
if (x>=-10 and x<-8) then exit(x-2)
else if (x>=-8 and x<-6) then exit(x+3)
else if (x>=-6 and x<=-2) then exit(x*x)
else if (x>-2 and x<2) then exit(abs(x))
else if (x>=2 and x<=4) then exit(x*x*x)
else if (x>4 and x<=6) then exit(3*x-4)
else if (x>6 and x<=8) then exit(4*x+1) ;
end;

Answer 2

if (x>=-10 and x<-8) then exit(x-2)
else if (x>=-8 and x<-6) then exit(x+3)
else if (x>=-6 and x<=-2) then exit(x*x)
else if (x>-2 and x<2) then exit(abs(x))
else if (x>=2 and x<=4) then exit(x*x*x)
else if (x>4 and x<=6) then exit(3*x-4)
else if (x>6 and x<=8) then exit(4*x+1)

Answer 3

麻烦说清楚问题啊。