Question

汇编 给定一个数据，把其值在屏幕上显示出来

Answer 1

data segment
buf db 30

actl db ?
str db 30 dup(?)
mess db 'what is your name ?',0dh,0ah,'$'
dmess db 0dh,0ah,'hello,$'
data ends
stack segment stack
db 400h dup(?)
stack ends
code segment
assume cs:code,ds:data,ss:stack
start:
main proc far
push ds
mov ax,0
push ax
mov ax,data
mov ds,ax
lea dx,mess
mov ah,09h
int 21h
lea dx ,buf ;将预先定义的变量送入，以便形成存储单元地址
mov ah,10 ;将从键盘输入的字符保存在以DS:DX为地址单元的内存中，字符数保存在(DS:DX+1)
int 21h
mov al,actl
cbw
mov si,ax
lea bx,str
mov [bx][si],byte ptr'!'
mov [bx][si+1],byte ptr'$'
lea dx,dmess
mov ah,09h
int 21h
lea dx,str
mov ah, 09h
int 21h
ret
main endp
code ends
end start
end start

Answer 2

DATA SEGMENT
STRING DB 'HELLO WORLD',ODH,OAH,'$' ;定义字符串
DATA ENDS
CODE SEGMENT
ASSUME CS: CODE, DS: DATA
START: MOV AX, DATA
MOV DS, AX
MOV DX,SEG STRING
MOV DS,DX ;待输出字符串段地址
MOV DX,OFFSET STRING ;待输邮字符串偏移地址
MOV AH,9 ;9号功能
INT 21H
MOV AH, 4CH
INT 21H
CODE ENDS
END START

Answer 3

DATA SEGMENT
BUF DW 4F59H
DATA ENDS
CODE SEGMENT
ASSUME CS: CODE, DS: DATA
START: MOV AX, DATA
MOV DS, AX
MOV SI, 0
P: MOV BX, BUF
MOV CH, 4
L: MOV CL, 4
ROL BX, CL
MOV DL, BL
AND DL, 0FH
CMP DL, 10
JB NEXT
ADD DL, 7
NEXT: ADD DL, 30H
MOV AH, 2
INT 21H
DEC CH
JNZ L
MOV AH, 4CH
INT 21H
CODE ENDS
END START