Question

C语言:写一个判断水仙花数的函数，在主函数中输入一个3位的整数，输出其是否是水仙花数的信息。

所谓水仙花数是指三位整数的各位上的数字的立方和等于该整数本身。例如：153就是一个水仙花数

Answer 1

#include<stdio.h>
int isflower(int x) //是 返回1，不是返回0.
{
if(x<100 || x>999) //不是三位数
{
printf("Input error");
return 0;
}
int a,b,c;
a = x%10; // 个位上的数
b =x/10%10; //十位上的数
c = x/100; //百位上的数
if(a*a*a + b*b*b + c*c*c == x)
{
return 1;
}
return 0;
}
int main()
{
int n;
scanf("%d",&n);
if(isflower(n))
{
printf("yes");
}
else
{
printf("no");
}
return 0;
}

Answer 2

#include "stdio.h"
#include "math.h"

void shuixianhua(int n)
{//水仙花数
int m=3,sum,temp;

if(999<n&&n<10000)m=4;
if(9999<n&&n<100000)m=5;
temp=n;
sum=0;
while (temp)
{
sum+=(int)pow(temp%10,m);
temp/=10;
}

if (sum==n)
printf("是水仙花数\n");
else printf("不是水仙花数\n");
}

int main()
{
int n;
printf("输入n：");
scanf("%d",&n);

shuixianhua(n);

return 0;
}

Answer 3

#include <stdio.h>
int main(void)
{
int shuixianhua;
int tmp = 0;
scanf("%d", &shuixianhua);
if (shuixianhua >= 100 && shuixianhua < 1000)
{
tmp = (shuixianhua / 100) * (shuixianhua /100) *(shuixianhua / 100);
tmp += ((shuixianhua % 100) /10)*((shuixianhua % 100) /10)*((shuixianhua % 100) /10);
tmp += (shuixianhua % 10)*(shuixianhua % 10)*(shuixianhua % 10);
if (tmp == shuixianhua)
{
printf("This is a shuixianhua\n");
}
else
{
printf("This isn't a shuuixianhua\n");
}
}
else
{
printf("what's your inputing is wrong\n");
}
return 0;
}

Answer 4

#include "stdio.h"
int isshui(int n)
{
int g,s,b;
g=n%10;
b=n/100;
s=(n/10)%10;
if(n==g*g*g+s*s*s+b*b*b)
return 1;
else
return 0;
}
int main(int argc, char* argv[])
{
int n;
scanf("%d",&n);
if(isshui(n))
printf("%d is shuixianhuashu.\n",n);
else
printf("%d is not shuixianhuashu.\n",n);
return 0;
}