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(3分之1)-(x^2+x)分之(x+1)-(3x^2+3x-6)分之(x-1)
=1/3-(x+1)/(x^2+x)-(x-1)/(3x^2+3x-6)
=1/3-(x+1)/[x(x+1)]-(x-1)/[(x-1)(3x+6)]
=1/3-1/x-1/[3(x+2)]
=x(x+2)/[3x(x+2)]-3(x+2)/[3x(x+2)]-x/[3x(x+2)]
=(x^2+2x-3x-6-x)/[3x(x+2)]
=(x^2-2x-6)/[3x(x+2)]
=(x^2-2x-6)/(3x^2+6x)
=1/3-(x+1)/(x^2+x)-(x-1)/(3x^2+3x-6)
=1/3-(x+1)/[x(x+1)]-(x-1)/[(x-1)(3x+6)]
=1/3-1/x-1/[3(x+2)]
=x(x+2)/[3x(x+2)]-3(x+2)/[3x(x+2)]-x/[3x(x+2)]
=(x^2+2x-3x-6-x)/[3x(x+2)]
=(x^2-2x-6)/[3x(x+2)]
=(x^2-2x-6)/(3x^2+6x)
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