Question

化简（根号下1-2sin40°cos40°）/[cos40°-根号下1-(sin50°)^2] O(∩_∩)O谢谢

过程 O(∩_∩)O谢谢

Answer 1

（根号下1-2sin40°cos40°）/[cos40°-根号下1-(sin50°)^2]
=（根号下sin^240°+cos^240°-2sin40°cos40°）/[cos40°-根号下(cos50°)^2]
=（-(sin40°-cos40°)）/[cos40°-cos50°]
=（cos40°-sin40°)）/[cos40°-sin40°]
=1

Answer 2

√(1-2sin40°cos40°)/[cos40°-√{1-(sin50°)^2]}
=√(sin40°-cos40°)^2/[cos40°-√(coc50°)^2]
=(cos40°-sin40°)/(cos40°-coc50°) cos40°>sin40°
=(cos40°-sin40°)/(cos40°-sin40°)
=1