Question

(-3x^3y^2+6x^4y^4-x^5y)/(-2/3x^2y)谢谢你们，教教我吧！ 已知分式方程（9/x-1）+1=1/x-1有增根，求a的值

Answer 1

(-3x^3y^2+6x^4y^4-x^5y)/(-2/3x^2y)
=x^2y(-3xy+6x^2y^3-x^3)/(-2/3x^2y)
=(-3xy+6x^2y^3-x^3)/(-2/3)
=(-3xy+6x^2y^3-x^3)*(-3/2)
=(9xy-18x^2y^3+3x^3)/2

已知分式方程（9/x-1）+1=1/x-1有增根
求a的值
题目有误，a在何处？

追问

9是a

追答

（a/x-1）+1=1/x-1
（a+x-1)/(x-1）=1/x-1
a+x-1=1
分式方程（9/x-1）+1=1/x-1有增根
则x=1
a+1-1=1
a=1