Question

初二因式分解计算题 急急急急!!!!!!

a^4＋a^2—a·b^3—ab=（“—”为减号，“·”为乘号，为了区分（ab）^2和 a乘以b的^2）

xy—xz—y^2+2yz=
x^2—xy+4x—4y=
x^3+3·x^2—4x—12=
x^3+6x^2+11x+6=
2·x(^3n) — 12·X(^2n ）· y（^2）+18·x(^n) · y(^4)= （这里有点乱，所以乘方都用括号打起来了）
（ax+by）^2+（ay—bx）^2+c^2 · x^2+c^2 · y^2
（x^2+y^2）^3+（z^2—x^2）^3—（y^2+z^2）^3
x^6+64·y^6+12x（^2）y(^2)—1

看着有点乱，其实抄在纸上不然，只限今晚！谢谢！越快越好
急！好的追加20分！

Answer 1

a^4+a^2-ab^3-ab
=a(a³-b³)+a(a-b)
=a(a-b)(a²+b²+ab+1)
xy—xz—y^2+yz
=xy-xz-y²+yz
=x(y-z)-y(y-z)
=(y-z)(x-y);
x^2—xy+4x—4y
=x(x+4)-y(x+4)
=(x-y)(x+4);
x^3+3·x^2—4x—12
=x²(x+3)-4(x+3)
=(x²-4)(x+3)
=(x-2)(x+2)(x+3)；
x^3+6x^2+11x+6
=x³+6x²+8x+3x+6
=x(x²+6x+8)+3(x+2)
=x(x+2)(x+4)+3(x+2)
=(x+2)(x²+4x+3)
=(x+2)(x+1)(x+3)
2·x(^3n) — 12·X(^2n ）· y（^2）+18·x(^n) · y(^4)
=2x^(3n)-6x^(2n)y²-6x^(2n)y²+18x^ny^4
=2x^(2n)(x^n-3y²)-6x^ny²(x^n-3y²)
=(2x^(2n)-6x^ny²)(x^n-3y²)
=2x^n(x^n-3y²)²;
（ax+by）^2+（ay—bx）^2+c^2 · x^2+c^2 · y^2
=a²x²+b²y²+a²y²+b²x²+c²x²+c²y²
=(a²+b²+c²)x²+(a²+b²+c²)y²
=(a²+b²+c²)(x²+y²)
（x^2+y^2）^3+（z^2—x^2）^3—（y^2+z^2）^3
=(x²+y²+z²-x²)[(x²+y²)²-(x²+y²)(z²-x²)+(z²-x²)²]-(y²+z²)³
=(y²+z²)(x^4+2x²y²+y^4-x²z²-y²z²+x^4+x²y²+z^4-2x²z²+x^4-y^4-2y²z²-z^4)
=(y²+z²)(3x^4+3x²y²-3x²z²-3y²z²)
=3(y²+z²)(x^4+x²y²-x²z²-y²z²)
=3(y²+z²)[x²(x²+y²)-z²(x²+y²)]
=3(y²+z²)(x²+y²)(x²-z²)
最后一题有问题啊

Answer 2

a^4＋a^2—a·b^3—ab=a(a³-b³)+a(a-b)=a(a-b)(a²+ab+b²)+a(a-b)=a(a-b)(a²+ab+b²+1)

xy—xz—y^2+2yz=x(y-z)-y(y-z)=(y-z)(x-y)

x^2—xy+4x—4y=x(x-y)+4(x-y)=(x-y)(x+4)

x^3+3·x^2—4x—12=x²(x+3)-4(x+3)=(x+3)(x²-4)=(x+3)(x-2)(x+2)

x^3+6x^2+11x+6=x³+6x²+9x+2x+6=(x+3)²+2(x+3)=(x+3)(x+5)

2·x(^3n) — 12·X(^2n ）· y（^2）+18·x(^n) · y(^4)=
=2x^n(x^2n-6x^ny^2+9y^4
=2x^n(x^n-3y²)²

（ax+by）^2+（ay—bx）^2+c^2 · x^2+c^2 · y^2
=a²x²+2abxy+b²y²+a²y²-2abxy+b²x²+c²x²+c²y²
=a²x²+b²y²+a²y²+b²x²+c²x²+c²y²
=a²(x²+y²)+b²(x²+y²)+c²(x²+y²)
=(x²+y²)(a²+b²+c²)

（x^2+y^2）^3+（z^2—x^2）^3—（y^2+z^2）^3
=(x²+y²+z²-x²)[(x²+y²)²-(x²+y²)(z²-x²)+(z²-x²)²]-(y²+z²)³
=(y²+z²)(x^4+2x²y²+y^4-x²z²-y²z²+x^4+x²y²+z^4-2x²z²+x^4-y^4-2y²z²-z^4)
=(y²+z²)(3x^4+3x²y²-3x²z²-3y²z²)
=3(y²+z²)(x^4+x²y²-x²z²-y²z²)
=3(y²+z²)[x²(x²+y²)-z²(x²+y²)]
=3(y²+z²)(x²+y²)(x²-z²)

x^6+64·y^6+12x（^2）y(^2)—1
=?

追问

不好意思，第二题：xy—xz—y^2+2yz后面再减个z^2变成 xy—xz—y^2+2yz—z^2
别的你确定都对么？给我一个肯定的“对！""或者“拿不准！”

追答

肯定对，你看我的等级就知道了，我本来就是老师

追问

呃，老师啊。。谢谢您，，第二题帮我再算一下，最后一题怎么了？？

追答

xy—xz—y^2+2yz—z^2
=x(y-z)-(y-z)²
=(y-z)(x-y+z)

最后一题题目有问题