Question

分解因式 (a-b)(x-y)+(b-a)(x+y)

Answer 1

(a-b)(x-y)+(b-a)(x+y)=（a-b）（x-y-x-y）=-2（a-b）y

Answer 2

(a-b)(x-y)-(a-b)(x+y)
=(a-b)(x-y-x-y)
=2y(b-a) 应该是吧自己看看 对的话采纳吧

Answer 3

解原式=(a-b)(x-y)-(a-b)(x+y)
=（a-b)[(x-y)-(x+y)]
=(a-b)(-2y)
=2y(b-a)

Answer 4

(a-b)(x-y)-(b-a)(x+y)=(a-b)(x-y)+(a-b)(x+y)=(a-b)(x-y+x+y)=2x(a-b)应该可以吧…