Question

eclipse下，用hibernate访问oracle。出现如下错误。

log4j:WARN No appenders could be found for logger (org.hibernate.cfg.Environment).
log4j:WARN Please initialize the log4j system properly.
Hibernate: select hibernate_sequence.nextval from dual
Exception in thread "main" org.hibernate.exception.SQLGrammarException: could not get next sequence value
at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:67)
at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:43)
at org.hibernate.id.SequenceGenerator.generate(SequenceGenerator.java:96)
at org.hibernate.event.def.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:99)
at org.hibernate.event.def.DefaultSaveOrUpdateEventListener.saveWithGeneratedOrRequestedId(DefaultSaveOrUpdateEventListener.java:187)
at org.hibernate.event.def.DefaultSaveEventListener.saveWithGeneratedOrRequestedId(DefaultSaveEventListener.java:33)
at org.hibernate.event.def.DefaultSaveOrUpdateEventListener.entityIsTransient(DefaultSaveOrUpdateEventListener.java:172)
at org.hibernate.event.def.DefaultSaveEventListener.performSaveOrUpdate(DefaultSaveEventListener.java:27)
at org.hibernate.event.def.DefaultSaveOrUpdateEventListener.onSaveOrUpdate(DefaultSaveOrUpdateEventListener.java:70)
at org.hibernate.impl.SessionImpl.fireSave(SessionImpl.java:535)
at org.hibernate.impl.SessionImpl.save(SessionImpl.java:523)
at org.hibernate.impl.SessionImpl.save(SessionImpl.java:519)
at dao.impl.UserDaoHibernateImpl.saveUser(UserDaoHibernateImpl.java:19)
at test.DaoTest.main(DaoTest.java:15)
Caused by: java.sql.SQLException: ORA-02289: 序列不存在

at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:439)
at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:395)
at oracle.jdbc.driver.T4C8Oall.processError(T4C8Oall.java:802)
at oracle.jdbc.driver.T4CTTIfun.receive(T4CTTIfun.java:436)
at oracle.jdbc.driver.T4CTTIfun.doRPC(T4CTTIfun.java:186)
at oracle.jdbc.driver.T4C8Oall.doOALL(T4C8Oall.java:521)
at oracle.jdbc.driver.T4CPreparedStatement.doOall8(T4CPreparedStatement.java:205)
at oracle.jdbc.driver.T4CPreparedStatement.executeForDescribe(T4CPreparedStatement.java:861)
at oracle.jdbc.driver.OracleStatement.executeMaybeDescribe(OracleStatement.java:1145)
at oracle.jdbc.driver.OracleStatement.doExecuteWithTimeout(OracleStatement.java:1267)
at oracle.jdbc.driver.OraclePreparedStatement.executeInternal(OraclePreparedStatement.java:3449)
at oracle.jdbc.driver.OraclePreparedStatement.executeQuery(OraclePreparedStatement.java:3493)
at oracle.jdbc.driver.OraclePreparedStatementWrapper.executeQuery(OraclePreparedStatementWrapper.java:1203)
at org.hibernate.id.SequenceGenerator.generate(SequenceGenerator.java:75)
... 11 more

Answer 1

在你的映射文件（.hbm.xml）中，其中有有个id的配置，在如下
<id name="typeid" type="java.lang.Integer">
<column name="TYPEID" precision="4" scale="0" />
<generator class="sequence" >
<param name="sequence">FILETYPE_ID</param>
</generator>
</id>
<param name="sequence">FILETYPE_ID</param>
添加你创建的序列号就可以了。

Answer 2

貌似是hibernate_sequence不存在

Answer 3

你有使用序列？看看是不是序列的问题

追问

没有使用序列啊
请问sequence和native的区别是？做什么用的？

追答

我只用过sequence。
上面不是报的这个错么could not get next sequence value。不就是不能获取序列的下一个值。你再仔细看看

追问

sequence怎么用？

追答

SequenceName.nextval
不过在hibernate中好像不是这样用的