
化简 [(x^2-4x-4)/(x+1)-(x^2+8x+13)/(x+2)]/(11x^2+33x+21)
1个回答
展开全部
化简 [(x²-4x-4)/(x+1)-(x²+8x+13)/(x+2)]/(11x²+33x+21)
解:原式=[(x²-4x-4)(x+2)-(x²+8x+13)(x+1)]/[(x+1)(x+2)(11x²+33x+21)]
=-(11x²+33x+21)/[(x+1)(x+2)(11x²+33x+21)]=(-1)/(x+1)(x+2)
解:原式=[(x²-4x-4)(x+2)-(x²+8x+13)(x+1)]/[(x+1)(x+2)(11x²+33x+21)]
=-(11x²+33x+21)/[(x+1)(x+2)(11x²+33x+21)]=(-1)/(x+1)(x+2)
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询