Question

用c++ do-while语句编程,求自然数1-10的和;并用for语句改写此程序。

Answer 1

#include

usingnamespacestd;

intmain()

{

intsum=0,n=1;

do{

sum=sum+n;

n++;

}while(n<=10);

cout<<"Thesumis:"<

usingnamespacestd;

intmain()

{

intsum=0;

for(intn=1;n<=10;n++)

{

sum+=n;

}

cout<<"Thesumis:"<

扩展资料

用c++do-while求平方根的迭代公式为：xn+1=(xn+a/xn)/2

#include<iostream>

#include<cmath>

usingnamespacestd;

intmain(){

floatx0,x1,a;

cout<<"输入一个正数："<<endl;

cin>>a;

if(a<0)cout<<a<<"不能开平方!"<<endl;

else{//有实数解的情况

x1=a/2;//x1用作保存结果

do{

x0=x1;

x1=(x0+a/x0)/2;

}while(fabs(x1-x0)>=1e-5);

cout<<a<<"的平方根为："<<x1<<endl;

}

return0;

}

Answer 2

#include<iostream.h>
int main(){
int sum=0,i=1;
do
{
sum=sum+i;
i++;
} while (i<11);
cout<<"The sum is:"<<sum<<endl;
return 0;
｝

/*****************************************************************************************
*****************************************************************************************/
#include<iostream.h>
int main(){
int sum=0,i;
for (i=1;i<11;i++)
{
sum+=i;
}
cout<<"The sum is:"<<sum<<endl;
return 0;
}

Answer 3

#include<iostream>
using namespace std;
int main()
{
int sum=0,n=1;
do {
sum=sum+n;
n++;
} while (n<=10);
cout<<"The sum is:"<<sum<<endl;
return 0;
｝
改写：
#include<iostream>
using namespace std;
int main()
{
int sum=0;
for (int n=1;n<=10;n++)
{
sum+=n;
}
cout<<"The sum is:"<<sum<<endl;
return 0;
}

Answer 4

#include〈iostream〉
using namespace std;
int main()
{
int i,sum=0;
cin>>i
do{
sum＋＝i;
i＋＋;
}while(i<＝10)
cout<<"sum＝"<<sum<<endl;
return 0;
}

Answer 5

我不回