Question

c++程序 某年某月某日是星期几

Answer 1

C 语言就可以了
实现如下：
//显示当前日期和时间
void show_time(void) {
struct tm *local;
long t;
static char wday[][3]={"日","一","二","三","四","五","六"};

time(&t);
local = localtime(&t); //返回结构指针

printf("现在是: %d.%02d.%02d(星期%s) ",local->tm_year+1900,++local->tm_mon,local->tm_mday,wday[local->tm_wday]);
printf(" %02d:%02d:%02d\n",local->tm_hour,local->tm_min,local->tm_sec);
}
如果是MFC的话，可以用CTime比较快！

追问

我需要的是用C++编写

Answer 2

//系统函数调用方法
#include <stdlib.h>;
#include <stdio.h>;
#include <time.h>;
#include <math.h>;

main( )
{

int j;
int k;
time_t *t;
int *jdate;
char *string;

struct tm *stm;

memset(&stm, 0x0, sizeof stm);

t = ( time_t * )( malloc( sizeof( time_t )));
time( t );
stm = localtime( t );
j = rtoday(&jdate);
k = rdayofweek(j);

switch(k)
{ case 0: string ="星期天";break;
case 1: string ="星期一";break;
case 2: string ="星期二";break;
case 3: string ="星期三";break;
case 4: string ="星期四";break;
case 5: string ="星期五";break;
case 6: string ="星期六";break;
}

printf("%4d年%2d月%2d日%2d时%2d分%2d秒今天是:%s\n",stm->;tm_year + 1900,stm->;tm_mon + 1,stm->;tm_mday,stm->;tm_hour,stm->;tm_min,stm->;tm_sec,string);

}

Answer 3

好吃的荷包蛋