(1+sin2x)/cos2x=tan(π/4+x)
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(1+sin2x)/cos2x
=[1-cos(2x+π/2)]/sin(π/2+2x)
=2sin²(x+π/4)/[2sin(π/4+x)cos(π/4+x)]
=sin(x+π/4)/cos(x+π/4)
=tan(π/4+x)
=[1-cos(2x+π/2)]/sin(π/2+2x)
=2sin²(x+π/4)/[2sin(π/4+x)cos(π/4+x)]
=sin(x+π/4)/cos(x+π/4)
=tan(π/4+x)
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