Question

[x^2y^2(x+y)^2-xy^2(x^3+xy^2)]/(1/2x^2y),其中x=1/2,y=1

在线等哦！！！

Answer 1

[x^2y^2(x+y)^2-xy^2(x^3+xy^2)]/(1/2x^2y)
=[x^2y^2(x+y)^2-x^2y^2(x^2+y^2)]/(1/2x^2y)
={x^2y^2[(x+y)^2-x^2-y^2]}/(1/2x^2y)
=x^2y^2[x^2+2xy+y^2-x^2-y^2]/(1/2x^2y)
=x^2y^2(2xy)/(1/2x^2y)
=x^2y^2(2xy)*[2/(x^2y)]
=4xy^2
=4*(1/2)*1
=2

Answer 2

[x^2y^2(x+y)^2-xy^2(x^3+xy^2)]/(1/2x^2y),
=2y(x²+2xy+y²)-(x^4y²+x²y^4)/(1/2x²y)
=2x²y+2xy²+2y³-2x²y-2y³
=2xy² 其中x=1/2,y=1
=2*1/2*1²
=1