Question

求不定积分∫xe^(x^2)dx?

Answer 1

∫xe^(x^2)dx=(1/2)e^(x^2))+C

Answer 2

凑微分∫xe^(-x^2)dx =∫e^(-x^2)d(x^2/2), 因为xdx=d(x^2/2) =-1/2*∫e^(-x^2)d(-x^2) =-1/2*e^(-x^2) -1/2*e^(